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Probabilities?
A certain electronics device has three independent components A,B and C. Within the first year of use, the probabilities that A, B and C will malfunction are 0.2,0.3 and 0.4 respectively. The device will not function properly under any of the following situation.
(1) A malfunctions, or (2) B and C both malfunction
Find the probability of the following event
the device function properly within the first year of use
4 個解答
- prisoner26535Lv 74 月前最愛解答
There are 3x independent cases when the device functions properly:
1. All A, B, C are good.
The probability = 0.8 x 0.7 x 0.6
2. A good, B bad, C good.
The probability = 0.8 x 0.3 x 0.6
3. A good, B good, C bad.
The probability = 0.8 x 0.7 x 0.4
So, the probability of working properly = p(1) + p(2) + p(3) = 0.704
- 匿名4 月前
- 匿名4 月前
P= 1 - (0.2 + 0.3 x 0.4) = 0.68