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數學:方程根之和積問題 (1)
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文字版:
It is given that α and β are the two distinct roots of the quadratic equation x² + kx + k = 0, where k is a constant.
Express 1/(α^n) + 1/(β^n) in terms of k and n.
數學:方程根之和積問題 (2)
2 個解答
- 知足常樂Lv 76 年前最愛解答
Let a = 1/α and b = 1/β.
a and b are distinct roots of ky² + ky + 1 = 0
root (a and b) = [-k ± √(k² - 4k)]/(2k) = [-1 ± √(1 - 4/k)]/2
Then, 1/αⁿ + 1/βⁿ = aⁿ + bⁿ
Any nicer form?
2015-06-22 00:43:22 補充:
The post is due soon.
Do you expect any specific nicer form?
1/αⁿ + 1/βⁿ = { [-1 + √(1 - 4/k)]ⁿ + [-1 - √(1 - 4/k)]ⁿ } / 2ⁿ
2015-06-22 20:48:25 補充:
Oh...
I expect there would be better answers...
2015-06-24 16:46:34 補充:
x² + kx + k = 0, with distinct roots α and β.
1 + k/x + k/x² = 0
k(1/x)² + k(1/x) + 1 = 0
Let a = 1/α and b = 1/β.
Then, a and b are distinct roots of ky² + ky + 1 = 0
roots a and b are [-k ± √(k² - 4k)]/(2k) = [-1 ± √(1 - 4/k)]/2
Then, 1/αⁿ + 1/βⁿ
= aⁿ + bⁿ
= { [-1 + √(1 - 4/k)]ⁿ + [-1 - √(1 - 4/k)]ⁿ } / 2ⁿ