Maths problem, thanks?

△ABC : △ADE = AC : AE

△ABC : 1 = (AC/AD) : (AE/AD)

△ABC = (1/cos60°) : cos60°

△ABC = 2 : 1/2

△ABC = 4 cm²

The answer is B.

∠B=∠E=90⁰

∠BAC=30⁰=∠EDA

∠BCA=60⁰=∠EAD

∴ △ABC ～ △DEA (AAA)

=> area of △ABC ：area of △DEA =AC² ：DA²

=> area of △ABC ：1 = AC² ：DA²

=> area of △ABC = (AC/DA)² . . . . . . . . . . . . . . . ①

　　　　　　　　　　　　　　　DA

From rt-angled △ADC, cos 60⁰ = ------

　　　　　　　　　　　　　　　AC

　　　　　　　　　　 　　½ = DA/AC

From ①： area of △ABC = (2/1)² = 4　　(ans : B )

△ABC : △ADE = AC : AE

△ABC : 1 = (AC/AD) : (AE/AD)

△ABC = (1/cos60°) : cos60°

△ABC = 2 : 1/2

△ABC = 4 cm²

The answer is B.

△ABC : △ADE = AC : AE

△ABC : 1 = (AC/AD) : (AE/AD)

△ABC = (1/cos60°) : cos60°

△ABC = 2 : 1/2

△ABC = 4 cm²

The answer is B

△ABC : △ADE = AC : AE 

△ABC : 1 = (AC/AD) : (AE/AD) 

△ABC = (1/cos60°) : cos60° 

△ABC = 2 : 1/2 

△ABC = 4 cm² 

The answer is B

△ABC : △ADE = AC : AE

△ABC : 1 = (AC/AD) : (AE/AD)

△ABC = (1/cos60°) : cos60°

△ABC = 2 : 1/2

△ABC = 4 cm²

The answer is B.

△ADE ～ △CAB

area△ADE : area△ABC = AD ² : AC ² = 1² : 2² = 1 : 4

4cm²

B. #

The answer is B