How do you graph the floor function f(x) = 3[x]?

Honestly, PatrickJMT explains floor functions well in this video:

https://www.youtube.com/watch?v=UQ3a2QH_-GU

f(x) = 3[x]

Basically anything you plug into the ' [x] ' portion it will round that number DOWN to the nearest whole integer. I'll give some example plot points:

f(2.3) = 3[2] = 6 , so the plot point is (2.3 , 6)

f(2.7) = 3[2] = 6 , so the plot point is (2.7, 6)

f(2.8) = 3[2] = 6 , so the plot point is (2.8 , 6)

Do you get the idea? it may seem weird at first because we're taught to round up if the decimal is ≥ .5 or down if it is < .5 but you don't follow that traditional rule of rounding here, you simply round DOWN to the nearest whole number even if the decimal is > .5 , within that [ ] box. This graph or any other based on a step function will essentially form horizontal lines or "steps" on the graph like seen in the video. It has this behavior because the rounding process.

To continue with this example, your next plotted "step" will be:

f(3.3) = 3[3] = 9 , so the plot point is (3.3 , 9)

f(3.9) = 3[3] = 9 , so the plot point is (3.9 , 9)

etc, you probably get the idea by now. Once you get to 4 on the graph, draw a hollow circle at the end to exclude it from that step. Then start graphing the 4.0 step, if you caught on at this point you'll know the next step will be a bunch of ( 4.n , 12) coordinate points, where ' n ' can be any number you want to put after the decimal point.

I hope I helped you more than confused you. Watch the video if you still don't understand. I also attached a picture of what your graph will look like, just don't forget to also do the bolded and hollow circles like shown on the vid.