數列A為項數是104的等差數列且級數和是2015;數列B為項數是104的等比數列且級數和是520;兩數列的順序乘積和(如同向量內積)為20000;求兩數列的逆序乘積和?

令:

數列A的首項為 a , 公差為 d ;

數列B的首項為 b , 公比為 r ;

兩數列的逆序乘積和為 S

分別將數列A, B 按數列順序寫成104維向量,

並令 B' 為 B向量的逆順序向量, 則:

A = ( a , a+d , a+2d , a+3d , ..... , a+102d , a+103d )

B = ( b , br , br^2 , br^3 , ..... , br^102 , br^103 )

B' = ( br^103 , br^102 , br^101 , ..... , br , b )

Σ A = 2015 , 所以:

104( 2a + 103d ) / 2 = 2015

2a + 103d = 2015*2/104 = 38.75

d = ( 38.75 - 2a ) / 103

Σ B = 520 , 所以:

b( 1 - r^104 ) / (1-r) = 520

1 + r + r^2 + ..... + r^102 + r^103 = 520/b

20000

= A．B

= ab + (a+d)br + (a+2d)br^2 + (a+3d)br^3 + ..... + (a+102d)br^102 + (a+103d)br^103

= ab(1+r+r^2+.....+r^102+r^103) + db(r+2r^2+3r^3+.....+102r^102+103r^103)

= ab(520/b) + db(r+2r^2+3r^3+.....+102r^102+103r^103)

= 520a + db(r+2r^2+3r^3+.....+102r^102+103r^103)

S

= A．B'

= abr^103 + (a+d)br^102 + (a+2d)br^101 + (a+3d)br^100 + ..... + (a+102d)br + (a+103d)b

= ab(r^103+r^102+.....+r+1) + db(r^102+2r^101+3r^100 +.....+102r+103)

= ab(520/b) + db(r^102+2r^101+3r^100 +.....+102r+103)

= 520a + db(r^102+2r^101+3r^100 +.....+102r+103)

令:

p = r + 2r^2 + 3r^3 + ..... + 102r^102 + 103r^103

q = r^102 + 2r^101 + 3r^100 + ..... + 102r + 103

則:

20000 = 520a + dbp

S = 520a + dbq

p + q

= 103 + 103r + ..... + 103r^102 + 103r^103

= 103( 1 + r + r^2 + ..... + r^102 + r^103 )

= 103 * 520/b

= 53560/b

S + 20000

= 1040a + db(p+q)

= 1040a + db*53560/b

= 1040a + 53560d

= 1040a + 53560( 38.75 - 2a )/103

= 1040a + 520( 38.75 - 2a )

= 20150

S = 20150 - 20000 = 150

Ans: 150