Yahoo 知識+ 將於 2021 年 5 月 4 日 (美國東岸時間) 停止服務,而 Yahoo 知識+ 網站現已轉為僅限瀏覽模式。其他 Yahoo 資產或服務,或你的 Yahoo 帳戶將不會有任何變更。你可以在此服務中心網頁進一步了解 Yahoo 知識+ 停止服務的事宜,以及了解如何下載你的資料。
Could someone help me with one-to-one functions?
So one of the exercises in the homework is :
g(x) = x^3+kx is one-to-one for k>0
f(x) = x^3+3x^2+kx
For what value of k is f(x) one to one?
I know that a function is 1-1 if x=y and f(x)=f(y) but then I don't know how I can figure out the value of k. Could someone please explain to me how I can do this so I can do it myself next time?
PS: There was a hint in the exercise which is: "write f(x) in the form (x - a)^3, and
determine the value for a for which f(x) reduces to the form of g(x); the squared term vanishes. Use then
the result for g(x)"
Thanks beforehand!
1 個解答
- cidyahLv 76 年前最愛解答
g(x)=x^3+kx is one-to-one for all values of k by the horizontal line test
http://www.mathwords.com/h/horizontal_line_test.ht...
f(x) = x^3+3x^2+kx
By the horizontal line test, f(x) is one-to-one for k >= 3