指數方程,求解

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請小心看清楚我以下沒有誤解你的發問：

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1.

3^(3x) = 27^(2x+1)

3^(3x) = (3^3)^(2x+1)

3^(3x) = 3^(3×(2x+1))

3x = 3×(2x+1)

3x = 6x+ 3

3x = -3

x = -1

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2.

4^(x+1) = 644^(x+1) = 4^3

x + 1 = 3

x = 2

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3.

2^(3x-1) = 4^x2^(3x-1) = (2^2)^x

2^(3x-1) = 2^(2 × x)

3x - 1 = 2x

x = 1

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4.

8^(3-x) = 1/648^(3-x) = 1/8²

8^(3-x) = 8^(-2)

3 - x = -2

x = 5

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5.

(1/3)^(x-1) = 27^(x-1)[3^(-1)]^(x-1) = (3^3)^(x-1)

3^(-1 × (x-1)) = 3^(3 × (x-1))

-1 × (x-1) = 3 × (x-1)

-(x - 1) = 3(x - 1)

-x + 1 = 3x - 3

4x = 4

x = 1