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Simple limit as x approaches infinity problem?
Limit as x approaches infinity
x / ( 2x + square root of 4x^2+x )
2 個解答
- HemantLv 71 十年前最愛解答
.. lim (x→∞) { x / [ 2x + √(4x²+x) ] } ......... Divide Num. & Den. both by x
= lim (x→∞) 1 / { [ 2x + √(4x²+x) ] / x } ... Now write Den. x as √(x²)
= lim (x→∞) 1 / { [ (2x)/(x) ] + [ √(4x²+x) / √(x²) ] }
= lim (x→∞) 1 / { 2 + √[ 4 + ( 1/x ) ] }
= 1 / { 2 + √( 4 + 0 ) }
= 1 / { 2 + 2 }
= 1 / 4 ................................. Ans.
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- 匿名4 年前
the cut back is only the derivative so keep in mind the quotient rule. the right cases the derivative of the backside - the backside cases the derivative of the right everywhere in the backside squared suitable derivative: 9+6x backside derivative: 1024x simplify and the respond is -(4608x^2-4102x-9) __________ (512x^2+a million)^2 sorry did no longer understand it became then raised to a million/3 if so: -(4608x^2+4102x-9) _________________ 3(3x^2-9x-4)^(2/3) * (512x^2+a million)^(4/3) I advise in case you will proceed with calc, you will desire to get your self a TI-89 calculator to ascertain your solutions Sorry then i can not help. I certainly have not accomplished them that way in years. i became attempting to keep in mind yet am drawing blanks. good success