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物理 MC choice

1. a light coil P is suspended to a spring balance by an inextensible string.

Another coil Q is connected to a battery and a rheostat. If the resistance of the

rheostat is suddenly reduced significantly, what happens to the reading of the

spring balance at that instant ?

A. Unchanged

B. Increased

C. Decreased

D. Cannot be determined as the polarity of the battery is not given.

2. Given the power dissipated in a fixed cable is P when a current I flows through it. If I is reduced by 25%, what is he percentage change of P ?

A. Reduced by 94%

B. Reduced by 75%

C. Reduced by 44%

D. Reduced by 25%

3. In the circuit , the rating of the light bulb is " 20 W, 5 V " . The efficiency of the

transformer is 60% . If the bulb works at its rated value , find the current in the

primary coil .

A. 0.1 A

B. 0.15 A

C. 0.2 A

D. 0.25 A

更新:

4. The rated values of both bulbs are " 12 W , 6 V " . The two bulbs are operating at their rated values. If the reading of the ammeter is 125 mA , fing the efficiency of the transformer .

A. 40 %

B. 60 %

C. 80 %

D. 100 %

更新 2:

5. PQ and RS are two parallel metal rails with separation L .

更新 3:

A metal rod XY resting on the rails moves with velocity v perpendicular to its length across a uniform magnetic field of flux density B pointing into the paper as shown. If the rod makes an angle θ with the rails , what is the potential difference across Q and S ?

更新 4:

(Assume that the rod is always in contact with the rails.)

6. A rigid rectangular conducting loop PQRS is connected to a cell as shown. It is held at rest horizontally within a uniform magnetic field which is parallel to the plane of the loop and perpendicular to its side RS.

更新 5:

Which of the following statements is / are correct ?

(1) The side RS of the loop experiences an upward magnetic force.

(2) The loop experiences a torque due to the magnetic field.

(3) The magnetic flux linking the loop due to the uniform magnetic field is zero .

A. (1) only

更新 6:

B. (3) only

C. (1) and (2) only

D. (2) and (3) only

2 個解答

評分
  • 天同
    Lv 7
    8 年前
    最愛解答

    1. I suppose there is a diagram associated with this question. Without the diagram, I assume coil Q is placed beneath coil P.

    Once the current in coil Q is suddenly decreased, the magnetic flux passing through coil P because of the current in coil Q decrases. By Lenz's Law, induced emf and thus induced current must flow so as trying to mainatain the magnetic flux. As such, the opposite polarity will be produced at the lower end of coil P to that at the upper end of coil Q. Attractive force is thus produced, causing the balance reading to increase.

    The answer is option B.

    2. New current I' = (1-0.25)I = 0.75I

    Initial power P = (I^2).R where R is the resistance of the cable

    New power P' = (I'^2).R = (0.75I)^2.R = 0.5625(I^2.R) = 0.5625P

    Percentage change of power = [(P' - P)/P] x 100%

    = (0.5625 - 1) x 100% = -43.75% (the -ve sign indcates a power reduction)

    The answer is option C

    3. Again, I suppose there is a diagram given, showing the turn-ratio of the transformer.

    Power delivered at primary coil = 20 x 100/60 w = 33.33 w

    Let the turn-ratio = N (N = turns in primary/turns in secondary)

    Then voltage at primary coil = 5N

    Current in primary = 33.33/5N

  • 8 年前

    天同 ,

    thankyou for your help !!!!

    thankyou !!!!

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