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Skylar B

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解答7

  • I have solved x-5√(x)+4=0 two different ways. What are the two different methods called?

    x-5√(x)+4=0

    x+4=5√(x)

    (x+4)^2=25x

    x^2+8x+16=25x

    x^2-17x+16=0

    (x-16)(x-1)=0

    x=1 or x=16

    substitute in x-5√(x)+4=0 ==> the 2 answers are correct ..

    2nd mothod:

    put u = √(x)==>x=u^2

    u^2-5u+4 =0

    (u-4)(u-1)=0

    u=4 or u=1

    x=u^2=16 or 1

    x={1,16}

    1 個解答Mathematics1 十年前

  • I need two methods for solving x-5√(x)+4=0.?

    I've been working on my algebra writing assignment for 2 days now and this is my last one and I have no clue!! Please help!!

    1 個解答Mathematics1 十年前

  • How do i graph 4x+5y-18=0?

    1 個解答Mathematics1 十年前

  • What do i do?

    OK I have played Field Hockey for three years now. There is this girl that joined the team last year..younger than me..but she is a real ***** to me. Trys to push me down on the field, talks about me when i walk away and i am considering not playin this year. But everyone is telling me not to worry about her. But heres the reason as to why i have not just punched her in her face and moved on.. she is my best friends sister. What do I do?

    2 個解答Friends1 十年前