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CAN SOMEONE PLEASE FIND THE PH LEVELS FOR THESE 5 CHEM PROBLEMS!!!!!?

1. 0.01 M HCl

2. 0.0010 M NaOH

3. 0.050 M Ca(OH)2

4. 0.030 M HBr

5. 0.150 M KOH

1 個解答

相關度
  • 4 年前
    最愛解答

    These are all strong acids or strong bases. As such, they completely ionize in solution. So:

    1. 0.01 M HCl When this completely ionizes, [H+] = 0.01 M (Are you OK with that?) So,

    pH = -log [H+] = - log 0.01 = 2.0

    2. 0.0010 M NaOH

    Here, [OH-] = 0.0010 M

    You can get to pH two different ways.

    (a) In any aqueous solution, [H+] X [OH-] = 1.00X10^-14

    So, [H+] = 1.00X10^-14 / 0.0010 = 1.0X10^-11

    pH = -log (1X10^-11) = 11.00

    (b) Calculate pOH as pOH = -log [OH-]. So

    pOH = -log (0.0010) = 3.00

    pH + pOH = 14.00

    pH = 14.00 - 3.00 = 11.00

    3. 0.050 M Ca(OH)2

    This is done the same was as 2., except that [OH-] = 2(0.050 M) = 0.10 M OH-. From here, follow #2.

    4. 0.030 M HBr (Just like #1)

    5. 0.150 M KOH (Just like #2)

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