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What is the molar mass of the sugar? 262.0 mL sample of sugar?
A 262.mL sample of a sugar solution containing 1.22 g of the sugar has an osmotic pressure of 30.3 mm Hg at 35 degrees C.
1 個解答
- Dr WLv 75 年前
"morse" equation
.. P = i M R T
where
.. P = osmotic pressure = 30.3mmHg
.. i = van't hoff factor = # of particles 1 particle of solute dissociates into = 1 in this case
.. M = molality = moles solute / Liter solution
.. R = gas constant = 0.08206 Latm/molK
.. T = temp in K = 308.15K
a few quick examples of i for further problems
.. 1 NaCl --> 1 Na(+) + 1 Cl(-).. 1 particle --> 2 particles... i=2
.. 1 MgCl2 --> 1 Mg(+2) + 2 Cl(-).. 1 particle ---> 3 particles.. i=3
.. 1 glucose --> 1 glucose.. glucose doesn't dissociate.. 1 --> 1 particle... i=1
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this problem
.. (1) use that equation and solve for M
.. (2) use volume solution (262mL) and M to determine moles solute
.. (3) molar mass = mass / mole
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more hints
.. M = P / (i x R x T) = 30.3mmHg x (1atm/760mmHg) / (1 x 0.08206Latm/molK x 308.15K)
.. M = ___ mol solute / liter solution
then
.. 262.0mL x (1L / 1000mL) x (___ mol / Liter) = ___ mol solute
then
.. molar mass = 1.22g / ___ mol solute = ___ g/mol
you get to finish
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btw.. the number i get about 3000g/mol is very high. But there are some polysaccharides in that range.