Can you please help me solve this chemistry math problem and show me how to do it?

Question

When 1.32 g of nonpolar solute was dissolved in 50.0 g of phenol, the latter's freezing point was lowered by 1.454 degrees C. Calculate the molar mass of the solute. Kf for phenol is 7.27 degrees C/m (degrees-kg/mol)

Dr W · Answer

besides the "morse equation" I showed you in your other problem here
https://answers.yahoo.com/question/index?qid=20160223105651AAXMJXa
there are two others related to freezing point depression and boiling point elevation you need to know
.. dTfp = Kf x m x i
.. dTbp = kb x m x i

where
.. dTfp = change in freezing point = fp pure solvent - fp solution
.. dTbp = change in boiling point = bp solution - bp pure solvent... note the order!
.. Kf = cryoscopic constant for the SOLVENT.. ... .i.e..fp depression constant
.. Kb = ebullioscopic constant for the SOLVENT... i.e  bp elevation constant
.. m = molality = moles solute / kg solvent
.. i = van't hoff factor... see my other answer for examples

***********
so.. 
.. (1) "nonpolar" solute means i=1
.. (2) use dTfp = Kf x m x i to calculation "m"
.. (3) use kg phenol and "m" to calculate moles solute
.. (4) molar mass solute = mass / mole

**********
more hints
.. m = dTfp / (kf x i) = 1.454°C / (7.27°C/m x 1) = ___ m
.. 0.050kg solvent x (___ mol solute  / kg solvent) = ___ mol solute
.. molar mass = 1.32g / ___ mol  solute = ___ g/mol

Can you please help me solve this chemistry math problem and show me how to do it?

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