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Can you please show me how to do this chemistry problem?
What is the normal boiling point of an aqueous solution that has a freezing point of -1.04 degrees C. Kf for water 1.86 degrees C/m (degrees C-kg/mol). Hint: Calculate the molality from the freezing point depression and use it to calculate the normal boiling point.
1 個解答
- hcbiochemLv 75 年前最愛解答
The equation for change in freezing point is
Change in freezing point = Kf m. So,
1.04 C = 1.86 C/m (m)
m = 0.559 molal solution
The equation for boiling point elevation is:
Change in boiling point = Kb m where Kb for water = 0.51 C/m
Change in BP = (0.51 C/m) (0.559 m) = 0.28 C.
Since water boils at 100.0 C, the boiling point of this solution will be 100.28 C.
