maths題'

1.

6a(p+3) - 10(p+3)^2

= [ 6a - 10(p+3) ] (p+3)

= (6a - 10p-30) (p+3)

2

(4x+y)^2 - (2x-y)^2

= [ (4x+y) - (2x-y) ] [ (4x+y) + (2x-y) ]

= (4x + y - 2x + y) (4x + y + 2x - y)

= (2x + 2y) (6x)

= 12(x + y) x

3.

(5x+y)^2 - 9(3x-y)^2

= (5x+y)^2 - (3(3x-y))^2

= [ (5x+y) - 3(3x-y) ] [ (5x+y) + 3(3x-y) ]

= (5x + y - 9x + 3y) (5x + y + 9x - 3y)

= (4y - 4x) (14x - 2y)

= 8(y - x) (7x - y)

2007-10-31 21:01:30 補充：

上面位第三條都錯左, 記得投我一票, 做得清楚, 一步一步

1.6a(p+3)-10(p+3)^2

=[6ap+18a-10p-30]^2

=12ap+36a-20p-60

2.(4x+y)^2-(2x-y)^2

=8x+2y-4x+2y

=4x+4y

3.(5x+y)^2-9(3x-y)^2

=10x+2y(-27x+9y)^2

=10x+2y-54x+18y

=-44+20y